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Thus N1 must be divisible by = 8*9*5*7 = 25 Now it is clear that the required number N less than 3000 does exist and is unique It is the number 2521 Problem 2 Find the number less than 3000 that leaves a remainder 1 when divided by 2, a remainder 2 when divided by 3, a remainder 3 when divided by by 4,How to use I mean, do we really need to explain how this calculator works? Iterate over a range 0, 9 using the variable j and perform the following steps Add the value of j to the variable remaining_sum and if remaining_sum is divisible by 3 and j is not equal to the digit at ith index, then add the value of count by 1 After performing the above steps, print the value of count as the answer Splash Screen Chapter 15 Divide By One Digit Numbers Click The Mouse Or Press The Space Bar To Continue Chapter 15 Divide By One Digit Numbers Click The Ppt Download What is 1/9 divided by 3

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